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#102
Binary Tree Level Order Traversal
Medium
Acceptance 0%
Editorial
description
Problem Description
Given the `root` of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level).
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Constraints
The number of nodes in the tree is in the range [0, 2000].
-1000 <= Node.val <= 1000
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Examples
Case #1
In:
root = [3,9,20,null,null,15,7]
Out:
[[3],[9,20],[15,7]]
Case #2
In:
root = [1]
Out:
[[1]]
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Graphs
Trees
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Amazon
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Microsoft
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Python 3
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C
C++ 17
Java
JavaScript
Python 3
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C++ 17
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from collections import deque class Solution: def levelOrder(self, root: TreeNode) -> list[list[int]]: pass
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